(x^2+4x-20)(x^2+16)=0

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Solution for (x^2+4x-20)(x^2+16)=0 equation:


Simplifying
(x2 + 4x + -20)(x2 + 16) = 0

Reorder the terms:
(-20 + 4x + x2)(x2 + 16) = 0

Reorder the terms:
(-20 + 4x + x2)(16 + x2) = 0

Multiply (-20 + 4x + x2) * (16 + x2)
(-20(16 + x2) + 4x * (16 + x2) + x2(16 + x2)) = 0
((16 * -20 + x2 * -20) + 4x * (16 + x2) + x2(16 + x2)) = 0
((-320 + -20x2) + 4x * (16 + x2) + x2(16 + x2)) = 0
(-320 + -20x2 + (16 * 4x + x2 * 4x) + x2(16 + x2)) = 0
(-320 + -20x2 + (64x + 4x3) + x2(16 + x2)) = 0
(-320 + -20x2 + 64x + 4x3 + (16 * x2 + x2 * x2)) = 0
(-320 + -20x2 + 64x + 4x3 + (16x2 + x4)) = 0

Reorder the terms:
(-320 + 64x + -20x2 + 16x2 + 4x3 + x4) = 0

Combine like terms: -20x2 + 16x2 = -4x2
(-320 + 64x + -4x2 + 4x3 + x4) = 0

Solving
-320 + 64x + -4x2 + 4x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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